Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
((F /\ r) || q || (~~(p || F) /\ ~~(p || F))) /\ ((F /\ r) || q || ~~(p || F))
⇒ logic.propositional.idempand((F /\ r) || q || ~~(p || F)) /\ ((F /\ r) || q || ~~(p || F))
⇒ logic.propositional.notnot((F /\ r) || q || p || F) /\ ((F /\ r) || q || ~~(p || F))
⇒ logic.propositional.falsezeroor((F /\ r) || q || p) /\ ((F /\ r) || q || ~~(p || F))