Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
((F /\ r) || ((q || ~~~~p) /\ (q || ~~p))) /\ ((F /\ r) || ((q || ~~~~p) /\ (q || ~~p)))
⇒ logic.propositional.idempand(F /\ r) || ((q || ~~~~p) /\ (q || ~~p))
⇒ logic.propositional.falsezeroandF || ((q || ~~~~p) /\ (q || ~~p))
⇒ logic.propositional.falsezeroor(q || ~~~~p) /\ (q || ~~p)
⇒ logic.propositional.notnot(q || ~~p) /\ (q || ~~p)
⇒ logic.propositional.idempandq || ~~p
⇒ logic.propositional.notnotq || p