Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

((F /\ r) || ((q || ~~(p || p)) /\ (q || ~~(p || p)))) /\ T

⇒ logic.propositional.truezeroand

(F /\ r) || ((q || ~~(p || p)) /\ (q || ~~(p || p)))

⇒ logic.propositional.falsezeroand

F || ((q || ~~(p || p)) /\ (q || ~~(p || p)))

⇒ logic.propositional.falsezeroor

(q || ~~(p || p)) /\ (q || ~~(p || p))

⇒ logic.propositional.idempand

q || ~~(p || p)

⇒ logic.propositional.notnot

q || p || p

⇒ logic.propositional.idempor

q || p