Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
((F /\ r) || ((q || ~~(p || p)) /\ (q || ~~(p || p)))) /\ T
⇒ logic.propositional.truezeroand(F /\ r) || ((q || ~~(p || p)) /\ (q || ~~(p || p)))
⇒ logic.propositional.falsezeroandF || ((q || ~~(p || p)) /\ (q || ~~(p || p)))
⇒ logic.propositional.falsezeroor(q || ~~(p || p)) /\ (q || ~~(p || p))
⇒ logic.propositional.idempandq || ~~(p || p)
⇒ logic.propositional.notnotq || p || p
⇒ logic.propositional.idemporq || p