Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
(((~q /\ ~(p -> q)) || F) -> (p /\ T)) || F
⇒ logic.propositional.falsezeroor((~q /\ ~(p -> q)) || F) -> (p /\ T)
⇒ logic.propositional.falsezeroor(~q /\ ~(p -> q)) -> (p /\ T)
⇒ logic.propositional.truezeroand(~q /\ ~(p -> q)) -> p
⇒ logic.propositional.defimpl~(~q /\ ~(p -> q)) || p
⇒ logic.propositional.demorganand~~q || ~~(p -> q) || p
⇒ logic.propositional.notnotq || ~~(p -> q) || p
⇒ logic.propositional.notnotq || (p -> q) || p
⇒ logic.propositional.defimplq || ~p || q || p