Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

(((F /\ r /\ F) || ~~q) /\ (r || ~~q)) || ~~(p /\ p)

⇒ logic.propositional.falsezeroand

((F || ~~q) /\ (r || ~~q)) || ~~(p /\ p)

⇒ logic.propositional.falsezeroor

(~~q /\ (r || ~~q)) || ~~(p /\ p)

⇒ logic.propositional.absorpand

~~q || ~~(p /\ p)

⇒ logic.propositional.notnot

q || ~~(p /\ p)

⇒ logic.propositional.notnot

q || (p /\ p)

⇒ logic.propositional.idempand

q || p