Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
(((F /\ r) || q || ~~(p || F)) /\ F /\ r) || (((F /\ r) || q || ~~(p || F)) /\ (q || ~~(p || F)))
⇒ logic.propositional.absorpand(F /\ r) || (((F /\ r) || q || ~~(p || F)) /\ (q || ~~(p || F)))
⇒ logic.propositional.absorpand(F /\ r) || q || ~~(p || F)
⇒ logic.propositional.falsezeroandF || q || ~~(p || F)
⇒ logic.propositional.falsezeroorq || ~~(p || F)
⇒ logic.propositional.notnotq || p || F
⇒ logic.propositional.falsezeroorq || p