Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
(((F /\ r) || q || ~~(p || F)) /\ ((F /\ r) || q || ~~(p || F))) || F
⇒ logic.propositional.falsezeroor((F /\ r) || q || ~~(p || F)) /\ ((F /\ r) || q || ~~(p || F))
⇒ logic.propositional.idempand(F /\ r) || q || ~~(p || F)
⇒ logic.propositional.falsezeroandF || q || ~~(p || F)
⇒ logic.propositional.falsezeroorq || ~~(p || F)
⇒ logic.propositional.notnotq || p || F
⇒ logic.propositional.falsezeroorq || p