Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
(((F /\ r) || q) /\ ((F /\ r) || q || ~~p)) || ((~~p || F) /\ ((F /\ r) || q || ~~p))
⇒ logic.propositional.absorpand(F /\ r) || q || ((~~p || F) /\ ((F /\ r) || q || ~~p))
⇒ logic.propositional.falsezeroandF || q || ((~~p || F) /\ ((F /\ r) || q || ~~p))
⇒ logic.propositional.falsezeroandF || q || ((~~p || F) /\ (F || q || ~~p))
⇒ logic.propositional.falsezeroorq || ((~~p || F) /\ (F || q || ~~p))
⇒ logic.propositional.falsezeroorq || (~~p /\ (F || q || ~~p))
⇒ logic.propositional.absorpandq || ~~p
⇒ logic.propositional.notnotq || p