Exercise algebra.equations.quadratic.no-abc

Description
solve a quadratic equation without abc-formula

Derivation

12-(2*x+3)^2 == 6

⇒ algebra.equations.coverup.onevar.minus-right

(2*x+3)^2 == 6

⇒ algebra.equations.coverup.power

2*x+3 == sqrt 6 or 2*x+3 == -sqrt 6

⇒ algebra.equations.coverup.onevar.plus

2*x == -3+sqrt 6 or 2*x+3 == -sqrt 6

⇒ algebra.equations.coverup.times

x == (-3+sqrt 6)/2 or 2*x+3 == -sqrt 6

⇒ algebra.equations.coverup.onevar.plus

x == (-3+sqrt 6)/2 or 2*x == -3-sqrt 6

⇒ algebra.equations.coverup.times

x == (-3+sqrt 6)/2 or x == (-3-sqrt 6)/2

⇒ algebra.equations.quadratic.distr-div

x == -3/2+sqrt 6/2 or x == -3/2-sqrt 6/2