Exercise logic.propositional.dnf.unicode
Description
Proposition to DNF (unicode support)
Firsts
Rule | logic.propositional.defimpl |
Location | [0,1,0,0,0] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
((T ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s))) ∨ ((¬(¬q ∨ p) ∨ ¬(q → p)) ↔ ((r ↔ s) ∨ ¬s))) ∧ (((¬(q → p) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s))) ∨ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s)))
ready: no
Rule | logic.propositional.defimpl |
Location | [0,1,0,1,0] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
((T ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s))) ∨ ((¬(q → p) ∨ ¬(¬q ∨ p)) ↔ ((r ↔ s) ∨ ¬s))) ∧ (((¬(q → p) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s))) ∨ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s)))
ready: no
Rule | logic.propositional.idempor |
Location | [0,1,0] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
((T ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s))) ∨ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s))) ∧ (((¬(q → p) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s))) ∨ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s)))
ready: no