Exercise logic.propositional.dnf.unicode
Description
Proposition to DNF (unicode support)
Firsts
Rule | logic.propositional.idempand |
Location | [0,0] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
((¬(q → p) ∧ ((r ↔ s) ∨ ¬s)) ∨ ¬¬(q → p)) ∧ ((¬(q → p) ∧ ((r ↔ s) ∨ ¬s) ∧ ¬(q → p) ∧ ((r ↔ s) ∨ ¬s)) ∨ ¬((r ↔ s) ∨ ¬s))
ready: no
Rule | logic.propositional.idempand |
Location | [1,0] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
((¬(q → p) ∧ ((r ↔ s) ∨ ¬s) ∧ ¬(q → p) ∧ ((r ↔ s) ∨ ¬s)) ∨ ¬¬(q → p)) ∧ ((¬(q → p) ∧ ((r ↔ s) ∨ ¬s)) ∨ ¬((r ↔ s) ∨ ¬s))
ready: no
Rule | logic.propositional.notnot |
Location | [0,1] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
((¬(q → p) ∧ ((r ↔ s) ∨ ¬s) ∧ ¬(q → p) ∧ ((r ↔ s) ∨ ¬s)) ∨ (q → p)) ∧ ((¬(q → p) ∧ ((r ↔ s) ∨ ¬s) ∧ ¬(q → p) ∧ ((r ↔ s) ∨ ¬s)) ∨ ¬((r ↔ s) ∨ ¬s))
ready: no