Exercise logic.propositional.dnf.unicode
Description
Proposition to DNF (unicode support)
Firsts
Rule | logic.propositional.idempand |
Location | [] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
(¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s))
ready: no
Rule | logic.propositional.idempand |
Location | [] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
(¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s))
ready: no
Rule | logic.propositional.idempand |
Location | [1] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
(¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s))
ready: no
Rule | logic.propositional.idempand |
Location | [1,1] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
(¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s))
ready: no
Rule | logic.propositional.truezeroand |
Location | [0,0,0] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
(¬(q → p) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s))
ready: no
Rule | logic.propositional.truezeroand |
Location | [1,0,0,0] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
(¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s))
ready: no
Rule | logic.propositional.truezeroand |
Location | [1,1,0,0,0] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
(¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s))
ready: no
Rule | logic.propositional.truezeroand |
Location | [1,1,1,0,0] |
Term | "Nothing" |
Focus | "Nothing" |
Environment | |
![](http://ideas.cs.uu.nl/images/external.png)
(¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(T ∧ (q → p)) ↔ ((r ↔ s) ∨ ¬s)) ∧ (¬(q → p) ↔ ((r ↔ s) ∨ ¬s))
ready: no