Exercise logic.propositional.consequence
Description
Prove that formula is a logical consequence of a set of formulas
All applications
Rule | introfalseleft |
Location | [0,0] |
![](http://ideas.cs.uu.nl/images/external.png)
F || ((p -> q) /\ (r -> s)) => (p /\ r) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [0,0,0] |
![](http://ideas.cs.uu.nl/images/external.png)
(F || (p -> q)) /\ (r -> s) => (p /\ r) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [0,0,0,0] |
![](http://ideas.cs.uu.nl/images/external.png)
((F || p) -> q) /\ (r -> s) => (p /\ r) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [0,0,0,1] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> (F || q)) /\ (r -> s) => (p /\ r) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [0,0,1] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (F || (r -> s)) => (p /\ r) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [0,0,1,0] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ ((F || r) -> s) => (p /\ r) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [0,0,1,1] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (r -> (F || s)) => (p /\ r) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [1] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (r -> s) => F || ((p /\ r) -> (q /\ s))
ready: no
Rule | introfalseleft |
Location | [1,0] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (r -> s) => (F || (p /\ r)) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [1,0,0] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (r -> s) => ((F || p) /\ r) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [1,0,1] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (r -> s) => (p /\ (F || r)) -> (q /\ s)
ready: no
Rule | introfalseleft |
Location | [1,1] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (r -> s) => (p /\ r) -> (F || (q /\ s))
ready: no
Rule | introfalseleft |
Location | [1,1,0] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (r -> s) => (p /\ r) -> ((F || q) /\ s)
ready: no
Rule | introfalseleft |
Location | [1,1,1] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (r -> s) => (p /\ r) -> (q /\ (F || s))
ready: no
Rule | logic.propositional.defimpl |
Location | [0,0,0] |
![](http://ideas.cs.uu.nl/images/external.png)
(~p || q) /\ (r -> s) => (p /\ r) -> (q /\ s)
ready: no
Rule | logic.propositional.defimpl |
Location | [0,0,1] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (~r || s) => (p /\ r) -> (q /\ s)
ready: no
Rule | logic.propositional.defimpl |
Location | [1] |
![](http://ideas.cs.uu.nl/images/external.png)
(p -> q) /\ (r -> s) => ~(p /\ r) || (q /\ s)
ready: no