Exercise logic.propositional.consequence
Description
Prove that formula is a logical consequence of a set of formulas
All applications
Rule | command.sort |
Location | [0,0,0] |
(q /\ ~r) || (r /\ ~q) => ~p || q || r
ready: no
Rule | command.sort |
Location | [0,0,1] |
(~r /\ q) || (~q /\ r) => ~p || q || r
ready: no
Rule | commor.sort |
Location | [0,0] |
(r /\ ~q) || (~r /\ q) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [0,0] |
F || (~r /\ q) || (r /\ ~q) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [0,0,0] |
F || (~r /\ q) || (r /\ ~q) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [0,0,0,0] |
((F || ~r) /\ q) || (r /\ ~q) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [0,0,0,0,0] |
(~(F || r) /\ q) || (r /\ ~q) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [0,0,0,1] |
(~r /\ (F || q)) || (r /\ ~q) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [0,0,1] |
(~r /\ q) || F || (r /\ ~q) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [0,0,1,0] |
(~r /\ q) || ((F || r) /\ ~q) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [0,0,1,1] |
(~r /\ q) || (r /\ (F || ~q)) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [0,0,1,1,0] |
(~r /\ q) || (r /\ ~(F || q)) => ~p || q || r
ready: no
Rule | introfalseleft |
Location | [1] |
(~r /\ q) || (r /\ ~q) => F || ~p || q || r
ready: no
Rule | introfalseleft |
Location | [1,0] |
(~r /\ q) || (r /\ ~q) => F || ~p || q || r
ready: no
Rule | introfalseleft |
Location | [1,0,0] |
(~r /\ q) || (r /\ ~q) => ~(F || p) || q || r
ready: no
Rule | introfalseleft |
Location | [1,1] |
(~r /\ q) || (r /\ ~q) => ~p || F || q || r
ready: no
Rule | introfalseleft |
Location | [1,1,0] |
(~r /\ q) || (r /\ ~q) => ~p || F || q || r
ready: no
Rule | introfalseleft |
Location | [1,1,1] |
(~r /\ q) || (r /\ ~q) => ~p || q || F || r
ready: no
Rule | logic.propositional.oroverand |
Location | [0,0] |
((~r /\ q) || r) /\ ((~r /\ q) || ~q) => ~p || q || r
ready: no
Rule | logic.propositional.oroverand |
Location | [0,0] |
(~r || (r /\ ~q)) /\ (q || (r /\ ~q)) => ~p || q || r
ready: no